Alan Arthur Australian rules footballer
Alan Arthur is a 114 years old Australian rules footballer from New York City, New York. Alan Arthur was born on July 25, 1864 (died on January 01, 1979, he was 114 years old) in New York City, New York.
About
No, he died on 01/01/1979, 45 years ago. He was 114 years old when he died. He died in Colorado Springs
Family
His mother is Ellen Lewis Herndon Arthur and his father is Chester A. Arthur. His mother was First LAdy of the United States His mother died at the age of 42 (Alan was 15 years old). When Alan born she was 26 years old. and Chester A. Arthur was 34 years old when Alan born. His father was an American president lawyer Union Army general.
Parents
Mother: Ellen Lewis Herndon Arthur
Father: Chester A. Arthur
Wife
Children
He had two children, Gavin (71, San Francisco astrologer/sexologist/grandson of U.S. President Chester A. Arthur) and Graham (88, Australian rules footballer) . When his first child, Gavin Arthur, was born, Alan Arthur was 36 years old.
Education
He graduated from Princeton University and Columbia Law School
What was Alan's zodiac sign?Alan Arthur zodiac sign was leo.
Other facts about Alan Arthur
| Position held | President , of: Cheyenne Mountain Country Club |
|---|---|
| Country of citizenship | United States Of America |
| Member of | Racquet And Tennis Club |
| Place of birth | New York City |
| Given name | Chester |
| Owner of | Edgeplain |
| Date of death | 1937-07-18T00:00:00Z |
| Place of death | Colorado Springs |
