William Digby Seymour British politician
William Digby Seymour is a 73 years old British politician from . William Digby Seymour was born on January 01, 1822 (died on January 01, 1895, he was 73 years old) in .
About
No, he died on 01/01/1895, 129 years ago. He was 73 years old when he died.
Family
His father Charles Seymour and Charles Seymour was 63 years old when William born. His father was a President of Yale University.
Parents
Mother: (?)
Father: Charles Seymour
Education
He graduated from Trinity College Dublin
Other facts about William Digby Seymour
| Position held | Member Of The 18th Parliament Of The United Kingdom , elected in: 1859 United Kingdom general election , end cause: dissolution of parliament , electoral district: Southampton , end time: 1865-07-06T00:00:00Z , start time: 1859-04-28T00:00:00Z |
|---|---|
| Work location | London |
| Name in native language | William Digby Seymour |
| Country of citizenship | United Kingdom Of Great Britain And Ireland |
| Date of death | 1895-01-01T00:00:00Z |
| Languages spoken, written or signed | English |
| Given name | William |
| Family name | Seymour. Show people with the surname Seymour |
William Digby Seymour Is A Member Of
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